How do you evaluate #5\sqrt { 8} - 3\sqrt { 18} + \sqrt { 2} #?

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Answer 1 · 2017-07-17T14:17:50

#5sqrt8-3sqrt18+sqrt2=2sqrt2#

#5sqrt8-3sqrt18+sqrt2#

= #5sqrt(2xx2xx2)-3sqrt(3xx3xx2)+sqrt2#

= #5sqrt(ul(2xx2)xx2)-3sqrt(ul(3xx3)xx2)+sqrt2#

= #5xx2sqrt2-3xx3sqrt2+sqrt2#

= #10sqrt22-9sqrt2+sqrt2#

= #(10-9+1)sqrt2#

= #2sqrt2#