What is the axis of symmetry and vertex for the graph y=-2x^2 +4x +2 ?

1 Answer
Jul 24, 2017

Axis of symmetry is x-1=0 and vertex is (1,4)

Explanation:

To find axis of symmetry and vertex, weshould convert the equation to its vertex form y=a(x-h)^2+k, where x-h=0 isaxis of symmetry and (h,k) is the vertex.

y=-2x^2+4x+2

=-2(x^2-2x)+2

=-2(x^2-2x+1)+2+2

=-2(x-1)^2+4

Hence axis of symmetry is x-1=0 and vertex is (1,4)

graph{(y+2x^2-4x-2)(x-1)((x-1)^2+(y-4)^2-0.02)=0 [-10, 10, -5, 5]}