Question

Question #5a4c9

Answer 1

`H_2SO_4 + CaCO_3 = CaSO_4 + CO_2 + H_2O`

`58g * (CaCO_3)/(100.09g) = 0.579mol`
`40g * (H_2SO_4)/(98.09g) = 0.407mol`

From these calculations, sulfuric acid is the limiting reactant.