A triangle has two corners with angles of # pi / 12 # and # pi / 12 #. If one side of the triangle has a length of #2 #, what is the largest possible area of the triangle?
1 Answer
Jul 29, 2017
Area Max = 0.984
Explanation:
Two angles =
If the base is = 2, then height of the triangle = tan 15 deg = 0.268
because tan 15 = h / 1.
Area for this triangle = 1/2 (2) (.268) = 0.268
BUT
If the sides are = 2
sin 15 = h/2 => h = 0.51
To find the base length
cos 15 = (b/2) / 2 => b = 3.86
Area = 1/2 (3.86) (0.51) = 0.984
