An object with a mass of $4 kg$ is revolving around a point at a distance of $5 m$ . If the object is making revolutions at a frequency of $5 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2017-08-02T14:30:36

Centripetal force is $19739.21N$

Centripetal force acting on a body in circular motion is given by

$F_c=(mv^2)/r$ , where $m$ is mass, $v$ is velocity and $r$ is the radius

As object moves at a frequency of $fHz$ , it means it moves

$2pirxxf$ in $1$ second and hence $v=2pirf$

and $F_c=m/rxx4pi^2r^2f^2=4pi^2mrf^2$

aas $m=4kg$ , $f=5Hz$ and $r=5m$

$F_c=4pi^2xx4xx5xx5^2=2000pi^2=19739.21N$

Answer 2 · 2017-08-02T14:31:45

The centripetal force is $=19.739kN$

The centripetal force is

$F=mv^2/r=mr omega^2$

The mass is $m=4kg$

The radius is $r=5m$

The angular velocity is $omega=2pif=10pi$

Therefore,

$F=4*5*(10pi)^2=19739N$

An object with a mass of 4 kg4 kg is revolving around a point at a distance of 5 m5 m. If the object is making revolutions at a frequency of 5 Hz5 Hz, what is the centripetal force acting on the object?