How do you find the standard equation given vertex at (0,-1) and passes through the point (2,2)?
1 Answer
Aug 10, 2017
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
where ( h , k ) are the coordinates of the vertex and a is a constant.
#"here "h=0" and "k=-1#
#rArry=ax^2-1#
#"to find a use the point "(2,2)" in the equation"#
#2=4a-1rArra=3/4#
#rArry=3/4x^2-1larrcolor(red)" in standard form"#
