What is the vertex form of y= 3x^2-11x+6 ?

1 Answer
Aug 11, 2017

(11/6, -49/12)

Explanation:

The x value of the axis of symmetry is the same as the x value of the vertex.

Use the axis of symmetry formula x=-b/(2a) to find the x value of the vertex.

x = (-(-11))/(2(3))

x = 11/6

Substitute x = 11/6 into the original equation for the y value of the vertex.

y = 3(11/6)^2 - 11(11/6) + 6

y = -49/12

Therefore, the vertex is at (11/6, -49/12).