Question

A charge of `5 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `27 J` to `18 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=1.8V`

Explanation:

The charge is `Q=It`

We apply Ohm's Law

`U=RI`

The power is

`P=UI`

And the energy is

`E=UIt`

`E=UQ`

and

`DeltaE=QDeltaU`

The voltage is

`DeltaU=(DeltaE)/Q=(27-18)/5=9/5=1.8V`