Question

How do you write the quadratic function in vertex form given vertex (-6,-7) and point (0,-61)?

Answer 1

`y=-3/2(x+6)^2-7`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`
where ( h , k ) are the coordinates of the vertex and a is a constant.

`"here "(h,k)=(-6,-7)`

`rArry=a(x+6)^2-7`

`"to find a substitute "(0,-61)" into the equation"`

`-61=36a-7rArra=-3/2`

`y=-3/2(x+6)^2-7larrcolor(red)" in vertex form"`