How do you find the vertex and the intercepts for $y = (x+4)(x-6)$ ?

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Answer 1 · 2017-08-18T11:01:00

Vertex is at $(1,-25)$ , $x$ intercepts are at $(-4,0) **and** (6,0)$ and $y$ intercept is at $(0,-24)$

$y = (x+4)(x-6) or y= x^2 -2x -24$ or

$y = x^2 -2x +1 -1 -24 or y = (x-1)^2 -25$

Comparing with vertex form of equation $y=a(x-h)^2+k ; (h,k)$

being vertex , here $h=1 , k = - 25$ , So vertex is at $(1,-25)$

To find $y$ intercept , putting $x=0$ in the equation we get

$y = (x+4)(x-6) or y = (0+4)(0-6) = -24$ ,

$y$ intercept is at $y =-24$ or at $(0,-24)$ . To find $x$ intercept ,

putting $y=0$ in the equation we get , $0 = (x+4)(x-6)$

$:. x =-4 , x = 6 :. x$ intercepts are at $x =-4 , x =6$ or at

$(-4,0) and (6,0)$ .

graph{(x+4)(x-6) [-80, 80, -40, 40]} [Ans]

How do you find the vertex and the intercepts for y = (x+4)(x-6) y = (x+4)(x-6) ?