What is the slope-intercept form of the equation with a slope of #4/3# and which goes through the point #(-2, -0)#?

1 Answer
Aug 18, 2017

See a solution process below:

Explanation:

We can use the point-slope formula to find the equation for this slope and point. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

First we can substitute the slope for #color(red)(m)# giving:

#y = color(red)(4/3)x + color(blue)(b)#

Next, we can substitute the values from the point in the problem and solve for #color(blue)(b)#:

#0 = (color(red)(4/3) xx -2) + color(blue)(b)#

#0 = -8/3 + color(blue)(b)#

#color(red)(8/3) + 0 = color(red)(8/3) - 8/3 + color(blue)(b)#

#8/3 = 0 + color(blue)(b)#

#8/3 = color(blue)(b)#

We can substitute #8/3# for #color(blue)(b)# and the slope from the problem to write the equation:

#y = color(red)(4/3)x + color(blue)(8/3)#