What is the new concentration of a solute when a #20mL# volume of a mother liquor at #2.0molL^-1# concentration is diluted to a volume of #100mL#?

Question

1341 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-20T06:13:35

The new concentration is #0.40*mol*L^-1#.

#"Molarity"="Moles of solute"/"Volume of solution"#

Initially, we have a molar quantity of #20*mLxx10^-3*L*mL^-1xx2*mol*L^-1=0.040*mol#, and this molar quantity is further diluted to #100*mL#....

#"Concentration"=(0.040*mol)/(100*mLxx10^-3*L*mL^-1)=0.40*mol*L^-1#.

What is the new concentration of a solute when a #20*mL# volume of a mother liquor at #2.0*mol*L^-1# concentration is diluted to a volume of #100*mL#?