Question

Find the maximum amount of ozone(O3) by removing all of its oxygen atomes?

Answer 1

There are `(196*g)/(98.08*g*mol^-1)=2.0*mol` `"sulfuric acid"`.

Explanation:

And thus we gots `2.0*molxx4=8*mol` oxygen ATOMS........which represents a mass of `8.0*molxx16.00*g*mol^-1=128*g` WITH RESPECT TO OXYGEN.....

And since `O_3` has a mass of `48.0*g*mol^-1`....we could conceivably make `(128.0*g)/(48.0*g*mol^-1)=2.67*mol`.

Please note that I cannot conceive of a process that would efficiently oxidize up the oxygen atoms in sulfuric acid to give ozone.....