Is the nonbonding orbital of #"NH"_3# a #p# orbital?

1 Answer
Sep 2, 2017

MOSTLY true. The lone pair is in a molecular orbital that is similar to a #p# orbital because it has significant #p# orbital characteristics, but it is not in a pure #p# atomic orbital.


Consider this orbital diagram of #"NH"_3#:

http://www.chemtube3d.com/

In a sense, I suppose the lone pair is in a #p#-like orbital... How we label it depends on how we treat the atomic orbitals.

  • In a hybridized treatment, one would place the nitrogen lone pair in an #sp^3# orbital, as seen in the above diagram. In this case, all four orbitals nitrogen uses for bonding are identical, with #75%# #p# character and #25%# #s# character.
  • In an unhybridized treatment, one would place the nitrogen lone pair in a molecular orbital with significant #p# characteristics, and the molecular orbital would primarily belong to the nitrogen.

http://www.ch.ic.ac.uk/

And in the above molecular orbital diagram, I would be referring to the molecular orbital labeled #2a_1#, which you can see involves interactions between more than one orbital.

Therefore, it is not a pure, nonbonding atomic orbital.

Either approach leads to the conclusion that the orbital contains significant #bbp# orbital characteristics, but it is not in a pure #p# orbital because it is not a purely nonbonding orbital.