If mass % of Oxygen in a monovalent metal carbonate is 48. Then find the number of atoms of metal present in 5mg of this metal carbonate sample?#( N_a = 6.022 * 10^23)#
2 Answers
Explanation:
We're asked to find the number of atoms of the metal present in
A monovalent metal carbonate includes a metal with a valence of one; i.e. a metal in group 1 (
#ul("M"_2"CO"_3#
We can use dimensional analysis to find the number of moles of the metal,
#5cancel("mg sample")((48cancel("mg O"))/(100cancel("mg sample")))((1cancel("g O"))/(10^3cancel("mg O")))((1cancel("mol O"))/(16.00cancel("g O")))((2color(white)(l)"mol M")/(3cancel("mol O"))) = color(red)(ul(0.0001color(white)(l)"mol M"#
Now, we can use Avogadro's number,
#color(red)(0.0001)cancel(color(red)("mol M"))((6.022*10^23color(white)(l)"atoms M")/(1cancel("mol M"))) = color(blue)(ulbar(|stackrel(" ")(" "6.0 xx 10^19color(white)(l)"atoms M"" ")|)# which I'll just round off to
#2# significant figures.
Therefore, there are
Explanation:
The metal is monovalent so the formula can be written
The mass of oxygen in the sample is given by:
To find the no. moles of oxygen we divide by the mass of 1 mole:
From the formula we can see that the no. moles of
To find the no. of atoms of