What is the vertex form of #5y = -2x^2-7x+2#?

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Answer 1 · 2017-09-29T12:07:52

Vertex form of equation is #y = -0.4( x+1.75)^2+1.625#

#5y= -2x^2-7x+2 or y = -2/5 x^2 -7/5x +2/5# or

#y = -0.4 x^2 -1.4x +0.4 or y = -0.4( x^2+3.5x)+0.4 # or

# y = -0.4( x^2+3.5x +1.75^2)+0.4- (1.75^2*-0.4) # or

#y = -0.4( x+1.75)^2+0.4+1.225 # or

#y = -0.4( x+1.75)^2+1.625# , comparing with standard vertex

form of equation #y = a(x-h)^2+k ; (h,k)# being vertex we find

# a = -0.4 , h= -1.75 , k=1.625 :.#.

Vertex is at #(-1.75,1.625)# and vertex form of equation is

#y = -0.4( x+1.75)^2+1.625# [Ans]