Question

How do you write `y=x^2+26x+68` in vertex form?

Answer 1

Vertex form of equation is `y=(x+13)^2-101`

Explanation:

`y= x^2+26x+68 or y= x^2+26x+169-169+68` or

`y=(x+13)^2-101` . Comparing with vertex form of equation

`y=a(x-h)^2+k ; (h,k)` being vertex we find here

`h=-13 , k=-101`. So vertex is at `(-13,-101)` and vertex

form of equation is `y=(x+13)^2-101` [Ans]