What is the vertex form of y=2x^2 -452x-68 ? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Archish R. Oct 14, 2017 vertex =(113,-25606) Explanation: y=2x^2-452x-68 vertex form: y=a(x-h)^2+k where (h,k) is the vertex y=2(x^2-2*113*x+12769)-25538-68 y=2(x-113)^2-25606 => vertex =(113,-25606) Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1496 views around the world You can reuse this answer Creative Commons License