We cannot do crossing over
Let's rewrite the expression
(x+1)/(x-1)<=2
(x+1)/(x-1)-2<=0
((x+1)-2(x-1))/(x-1)<=0
((x+1-2x+2))/(x-1)<=0
((3-x))/(x-1)<=0
Let f(x)=((3-x))/(x-1)
Let's build a sign chart
color(white)(aaaa)xcolor(white)(aaaa)-oocolor(white)(aaaaaaa)1color(white)(aaaaaaa)3color(white)(aaaaaaa)+oo
color(white)(aaaa)x-1color(white)(aaaaa)-color(white)(aaaa)||color(white)(aa)+color(white)(aaaaaaa)+
color(white)(aaaa)3-xcolor(white)(aaaaa)+color(white)(aaaa)||color(white)(aa)+color(white)(aa)0color(white)(aaaa)-
color(white)(aaaa)f(x)color(white)(aaaaaa)-color(white)(aaaa)||color(white)(aa)+color(white)(aa)0color(white)(aaaa)-
Therefore,
f(x)>=0 when x in (-oo,1) uu [3,+oo)
graph{(x+1)/(x-1)-2 [-12.66, 12.65, -6.33, 6.33]}