Given #y=x^2-5x+4#, how do you write the equation of the axis of symmetry?

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Answer 1 · 2017-11-02T13:23:11

Axis of symmetry is #x =2 1/2#

The equation given is that for a parabola because of the #x^2# term.

A parabola has the standard form: # y = ax^2 +bx +c#

Parabolas are always symmetrical about a vertical line called its axis of symmetry.

It will always have the equation #x = ...# which indicates what the #x#-intercept is.

To find the axis of symmetry, use : #x = (-b)/(2a)#

For this equation: #y = x^2 -5x+4#

#x= (-(-5))/(2(1))#

#x = 5/2 = 2 1/2#