How do you solve $3 (1 - 3 x) = 2 (- 4 x + 7)$ $3(1-3x)=2(-4x+7)$ ?

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How do you solve $3 (1 - 3 x) = 2 (- 4 x + 7)$ $3(1-3x)=2(-4x+7)$ ?

1 Answer

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Answer 1 · 2017-11-06T06:19:34

$x = - 11$ $x=-11$

Explanation:

First, expand both sides of the equation.

$3 - 9 x = - 8 x + 14$ $3-9x=-8x+14$

Make sure that the variable, x, is only on one side of the equation. Add 9x to each side.

$3 - 9 x + 9 x = - 8 x + 14 + 9 x$ $3 -9x +9x = -8x +14 +9x$

$3 = 14 + x$ $3 = 14 +x$

Subtract 14 from both sides.

$3 - 14 = 14 + x - 14$ $3-14=14+x-14$
$- 11 = x$ $-11=x$

Check the solution:
$3 (1 - 3 [- 11]) = 2 (- 4 [- 11] + 7)$ $3(1-3[-11])=2(-4[-11]+7)$
$3 (1 - - 33) = 2 (44 + 7)$ $3(1--33)=2(44+7)$
$3 (1 + 33) = 2 (44 + 7)$ $3(1+33)=2(44+7)$
$3 (34) = 2 (51)$ $3(34)=2(51)$
$102 = 102$ $102=102$

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How do you solve $3 (1 - 3 x) = 2 (- 4 x + 7)$ $3(1-3x)=2(-4x+7)$ ?

1 Answer

Explanation:

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How do you solve $3 (1 - 3 x) = 2 (- 4 x + 7)$ $3(1-3x)=2(-4x+7)$ ?