An object with a mass of # 3 kg# is traveling in a circular path of a radius of #7 m#. If the object's angular velocity changes from # 6 Hz# to # 9 Hz# in #3 s#, what torque was applied to the object?

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Answer 1 · 2017-11-11T01:24:36

#"923.6 Nm"# of torque was applied to object.

Torque is rate of change of angular momentum.

#T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t#

#T = ("3 kg × (7 m)"^2 × 2 π (9 - 6) "Hz")/"3 s" = "923.6 Nm"#