A solid disk with a radius of #8 m# and mass of #6 kg# is rotating on a frictionless surface. If #960 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #25 Hz#?

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Answer 1 · 2017-11-11T01:45:56

#"6.1 Nm"# of Torque is applied on disc.

#"Power = Torque × Angular Velocity"#

#"Torque" = "Power" / "Angular Velocity" = ("960 Watt") / ("2 π × 25 Hz") = "6.1 Nm"#