Question

How do you find the period of `y=sin(x/3)`?

Answer 1

We have that the period of `sin(x)` is `2pi`. Thus, with a horizontal stretch of a factor of `3`, as given in the above equation, the period will become `2pi * 3 = 6pi`.

Graphical confirmation:

graph{sin(x/3) [-10, 10, -5, 5]}

Hopefully this helps!