How do you factor the monomial $- 20 m^{5} n^{2}$ $-20m^5n^2$ completely?

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Answer 1 · 2017-11-20T18:10:52

We can write the prime factors of $- 20 m^{5} n^{2}$ $-20m^5n^2$ as:

$- 2 \times 2 \times 5 \times m \times m \times m \times m \times m \times n \times n$ $-2 xx 2 xx 5 xx m xx m xx m xx m xx m xx n xx n$

How do you factor the monomial −20m5n2-20m^5n^2 completely?