Each pair of points (5.4 , 3) and (2, y) is on the graph of an inverse variation, how do you find the missing value?
1 Answer
Nov 27, 2017
Explanation:
#"the initial statement is "yprop1/x#
#"to convert to an equation multiply by k the constant"#
#"of variation"#
#rArry=kxx1/x=k/x#
#"to find k use "(5.4,3)" that is x = 5.4 and y = 3"#
#y=k/xrArrk=yx=3xx5.4=16.2#
#"the equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=16.2/x)color(white)(2/2)|)))#
#"when "x=2#
#y=16.2/2=8.1#
#rArr(2,y)=(2,8.1)#
