Two corners of an isosceles triangle are at $(1 ,7 )$ and $(2 ,3 )$ . If the triangle's area is $6$ , what are the lengths of the triangle's sides?

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Answer 1 · 2017-12-05T13:16:51

Measure of the three sides are (4.1231, 3.5666, 3.5666)

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Length $a = sqrt((2-1)^2 + (3-7)^2) = sqrt 17 = 4.1231$

Area of $Delta = 6$
$:. h = (Area) / (a/2) = 6 / (4.1231/2) = 6 / 2.0616 = 2.9104$

$side b = sqrt((a/2)^2 + h^2) = sqrt((2.0616)^2 + (2.9104)^2)$
$b = 3.5666$

Since the triangle is isosceles, third side is also $= b = 3.5666$

Two corners of an isosceles triangle are at (1 ,7 )(1 ,7 ) and (2 ,3 )(2 ,3 ). If the triangle's area is 6 6 , what are the lengths of the triangle's sides?