Question

How do you graph `Y= 3(x - 2)^2 + 5`?

Answer 1

Check this out

Explanation:

graph{3*(x-2)^2+5 [-2, 10, 4.08, 20]}

Assume values for x. Calculate values for y and plot
Let us take x values 0,1,2,3,4. Then
If `x = 0` then `y = 3(0-2)^2+5 = 17`
If `x=1` then `y = 3(1-2)^2+5 = 8`
If `x =2` then `y = 3(2-2)^2+5 = 5`
If `x = 3` then `y = 3(3-2)^2+5 = 8`
If `x = 4` then `y = 3(4-2)^2+5 = 17`

Now plot `(0,17),(1,8),(2,5),(3,8),(4,17)`