What is the vertex form of y= 6x^2-9x+3 ?
2 Answers
Explanation:
To complete the square of the equation, first take out the 6:
Then do the bit in the brackets:
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
"to obtain this form use the method of"
color(blue)"completing the square"
• " the coefficient of the "x^2" term must be 1"
rArry=6(x^2-3/2x)+3
• " add/subtract "(1/2"coefficient of x-term")^2" to"
x^2-3/2x
rArry=6(x^2+2(-3/4)xcolor(red)(+9/16)color(red)(-9/16))+3
rArry=6(x-3/4)^2-27/8+3
rArry=6(x-3/4)^2-3/8larrcolor(red)"in vertex form"