Two corners of a triangle have angles of $(5 pi )/ 8$ and $( pi ) / 2$ . If one side of the triangle has a length of $8$ , what is the longest possible perimeter of the triangle?

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Answer 1 · 2017-12-20T10:51:48

Sum needs correction as two angles account for greater than $pi$

Given :
/_ A = (5pi)/8, /_B = pi / 2#

Sum of all the three angles must be = $pi$

$pi / 2 + ((5pi)/8) = ((9pi)/8)$ which is greater than $pi$

As sum of the given two angles exceeds $pi$ ,
such a triangle cannot exist.

Two corners of a triangle have angles of (5 pi )/ 8 (5 pi )/ 8 and ( pi ) / 2 ( pi ) / 2 . If one side of the triangle has a length of 8 8 , what is the longest possible perimeter of the triangle?