Question

Question #e5006

Answer 1

`=96.2gCaCO_3`

Explanation:

1. Write the skeleton and balance the given equation
   `Ca(OH)_2(s)+CO_2(g)>CaCO_3(s)+H_2O(g)`
2. Find the molar mass of `CaCO_3` as the involved compound as specified in the problem.
   `=(100g)/(mol)`
3. Since the given data is already expressed in `mol`, conversion per convention is no longer necessary in this case.
4. Referring to the balanced equation shown above for the mole ratio, find the `etaCaCO_3` through molar conversion; i.e.,
   `=0.962cancel(molCa(OH))_2xx(1molCaCO_3)/(1cancel(molCa(OH)_2))`
   `=0.962molCaCO_3`
5. Now, find the `"mass"(m)` of `CaCO_3`, knowing the `etaCaCO_3` as computed, and the molar mass of the compound for the conversion.
   `=0.962cancel(molCaCO_3)xx(100gCaCO_3)/(1cancel(molCaCO_3))`
   `=96.2gCaCO_3`