Question

How do you find the vertex of `y= -x^2+ 4x + 2`?

Answer 1

`-(x-2)^2+6`

Explanation:

`−x^2+4x+2`

`=>-1*[x^2-4x-2]`

`=>-1*[(x^2-2*2x+2^2)-2^2-2]`

`=>-1*[(x-2)^2-4-2]`

`=>-1*[(x-2)^2-6]`

`(-(x-2)^2+6)/`