How do you write f(x)= -2x^2+6x+2 in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Raiyan · Dec 30, 2017 - 2 ( x - 3/2 )^2 + 13/2 Explanation: - 2x^2 + 6x + 2 = - 2 (x^2 - 3x) + 2 = - 2 (x^2 - 2 * 3/2 * x + (3/2)^2 - (3/2)^2) + 2 = - 2 (x -3/2)^2 + 2 + 9/2 = - 2 (x - 3/2)^2 + 13/2 Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2445 views around the world You can reuse this answer Creative Commons License