How do you solve #3x^2<5x# using a sign chart?

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Answer 1 · 2018-01-01T15:21:52

Solution: # 0 < x < 5/3 or (0,5/3)#

#3x^2 <5x or 3x^2-5x < 0 or x(3x-5)< 0 #

Critical points are # x=0 and 3x-5=0 or x=5/3#

Sign chart:

When #x< 0# sign of #x(3x-5) # is # (-) * (-)= (+) ; > 0#

When # 0 < x < 5/3 # sign of #x(3x-5) # is

# (+) * (-)= (-) ; < 0#

When # x > 5/3 # sign of #x(3x-5) # is # (+) * (+) = (+) ; > 0#

Solution: # 0 < x < 5/3 or (0,5/3)#