How do you solve # 4x - y = 30#, # 4x + 5y = -6# by graphing and classify the system?
1 Answer
See a solution process below:
Explanation:
To solve this problem, plot two points for each equation and draw a line through the points.
Equation 1:
For
For
graph{(x^2 + (y + 30)^2 - 0.75)((x - 5)^2 + (y + 10)^2 - 0.75)(4x - y - 30) = 0 [-100, 100, -50, 50]}
Equation 2:
For
For
graph{(x^2 + (y + 6/5)^2 - 0.75)((x + 3/2)^2 + y^2 - 0.75)(4x + 5y + 6)(4x - y - 30) = 0 [-100, 100, -50, 50]}
We can see the lines cross at:
These two equations are consistent and independent because the have a solution and only one solution.
graph{((x-6)^2 + (y + 6)^2 - 0.05)(4x + 5y + 6)(4x - y - 30) = 0 [-2, 14, -7, 1]}