How do you find the period and amplitude of $y=3sin2x$ ?

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Answer 1 · 2018-01-22T02:08:48

Amplitude is the value of $a$ , which is $3$ in this case. This means the vertical distance from the centre line to the max/min is $3$ units.

The period is given by $2pi/b = (2pi)/(2) = pi$ . Which means that it takes the function $pi$ units to repeat itself.

Hopefully this helps!

How do you find the period and amplitude of y=3sin2xy=3sin2x?