Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `33 J` to `9 J`, what is the voltage between points A and B?

Answer 1

`4V`

Explanation:

Relationship between voltage (`V`) and change in potential energy (`delta U`) is given as,

`V= (delta U)/q` (i.e the energy change for bringing a charge `q` in between two points )

Given, `delta U = (33-9) J=24 J` and, `q=6C`

So, Volage is `(24/6) V=4V`