How do you graph #y=sec (x/2)#?

1 Answer
Feb 7, 2018

Please read Explanation.

Explanation:

The first step to graphing a reciprocal function is to expand the function with the definition of the reciprocal function. In this case:

#sectheta=1/costheta#

So, to put it in the actual function:

#sec(x/2)=1/cos(x/2)#

Now, graph the wave of #cos(x/2)# with a dotted line. The graph starts at #(0,1)# and has a period of #(2pi)/(1/2)# or #4pi#. (drawn in green)

https://www.desmos.com/calculator

Next, mark a dot on the points where the wave reaches a maximum or a minimum (blue in the picture). Also, mark asymptotes (vertical lines) wherever the wave crosses the #x#-axis (red):

https://www.desmos.com/calculator

Lastly, you can draw the actual function. To do this, you have to draw figures that look like parabolas between the red lines. If the blue point in that section is above the #x#-axis, then the "parabola" is also above the #x#-axis. If it is below, then the "parabola" is below also. In the end, it looks like this (in purple):

https://www.desmos.com/calculator

Here's just the #sec(x/2)# graph:

https://www.desmos.com/calculator

I created a Desmos website with all of this information:
https://www.desmos.com/calculator/uquf0kxbeo