Question

How do you find the minimum and maximum value of `y=(x-6)^2+3`?

Answer 1

`x=6` is the minimum and we don't have a maximum

Explanation:

It's a quadratic equation with positive "a". So, it doesn't have a maximum value, just a minimum.

First we have a square and the plus three. If x is a real number, its square must be non-negative. So, taking this and the fact that three is constant, the minimum value happens when `x-6=0=>x=6`