Question

If 15 moles of water was made in this reaction, how many grams of carbon dioxide were made? `H_2CO_3rarrH_2O+CO_2`

Answer 1

`660.15"g"` of carbon dioxide was produced.

Explanation:

We have the equation `H_2CO_3rarrH_2O+CO_2`.

The moles of water and carbon dioxide are in the ratio `1:1`.

So `15` moles of water and `15` moles of carbon dioxide are produced.

The formula for moles is `n=m/M`, where `m` is the mass of the substance and `M` its molar mass.

Rearranging the equation we get `m=nM`.

We have `15"mol"` of carbon dioxide and the molar mass of the gas is `44.01"g"/"mol"`.

Inputting:

`m=15*44.01`

`m=660.15"g"` of carbon dioxide was produced.