How do you solve $6 (x + 8) = 18$ $6(x+8)=18$ ?

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How do you solve $6 (x + 8) = 18$ $6(x+8)=18$ ?

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Answer 1 · 2018-03-02T02:17:53

the answer is $x = - 5$ $x=-5$

Explanation:

$6 x + 48 = 18$ $6x+48=18$
$- 48$ $-48$
$6 x = - 30$ $6x=-30$
divide $6$ $6$ from both sides
$x = - 5$ $x=-5$

Answer 2 · 2018-03-02T02:17:58

No need to expand the brackets in the first step
Simply transfer the 6
$x + 8 = \frac{18}{6}$ $x+8=18/6$
$x + 8 = 3$ $x+8=3$
Transfer 8
$x = 3 - 8$ $x=3-8$
$x = - 5$ $x=-5$

Answer 3 · 2018-03-02T02:19:14

$x = - 5$ $x=-5$

Explanation:

Apply the Distributive Property on the left side, which tells us that $a (b \pm c) = a b \pm a c$ $a(b+-c)=ab+-ac$

$6 (x + 8) = 18 \Leftrightarrow 6 x + 6 (8) = 18$ $6(x+8)=18hArr6x+6(8)=18$

Simplifying, we have

$6 x + 48 = 18$ $6x+48=18$

We now want to isolate $x .$ $x.$ Subtract $48$ $48$ from both sides:

$6xcancel(+48-48)=18-48$

$6x=-30$

Divide both sides by $6:$

$(cancel6x)/cancel6=-30/6$

$x=-5$

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How do you solve $6 (x + 8) = 18$ $6(x+8)=18$ ?

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