Question

A charge of `16 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `28 J` to `12 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=1V`

Explanation:

Apply the equation

`"Energy"(J)"` `= " Electric potential(V)"xx"Charge (C)"`

The charge is `Q=16C`

The change in energy is `DeltaE=28-12=16J`

The voltage is

`U=(DeltaE)/(Q)=16/16=1V`