If #(-7, y)# is a solution to the equation #2x-7y-4x=0#, what is the value of #y#?

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Answer 1 · 2018-03-04T17:33:55

#y = 2#

Let's move terms based on the variable that it is with.

#2x - 4x = 7y#

So we know that #x = -7#.

#2(-7) - 4(-7) = 7y#

Which is simplified to...

#-14 + 28 = 7y#
#14 = 7y#

Divide both sides by #7# to isolate and solve for #y# and you should get #y = 2#.