Question

How do you find the slope and y-intercept for the line `5x-y+2=0`?

Answer 1

Just arrange the equation in `y=mx+c` form,where `m` is the slope and `c` is the `Y` intercept.

So,given equation in `5x-y+2=0`

or, `y=5x+2`

so,comparing with `y=mx+c` we get, `m=5` and `c=2`

Now,see the graph below to match the result obtained. graph{5x-y+2=0 [-10, 10, -5, 5]}

Answer 2

See a solution process below:

Explanation:

We can put the equation for the line in slope-intercept form. The slope-intercept form of a linear equation is: `y = color(red)(m)x + color(blue)(b)`

Where `color(red)(m)` is the slope and `color(blue)(b)` is the y-intercept value.

`5x - y + 2 = 0`

`5x - y + color(red)(y) + 2 = 0 + color(red)(y)`

`5x - 0 + 2 = y`

`5x + 2 = y`

`y = color(red)(5)x + color(blue)(2)`

Therefore:

• The slope is: `color(red)(m = 5)`

• The `y`-intercept is: `color(blue)(b = 2)` or `(0, color(blue)(2))`