How do you solve #\sqrt { 7u + 6} = \sqrt { 5u + 16}#?

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Answer 1 · 2018-03-10T02:24:32

#u=5#

Refer to the explanation for the process.

Solve:

#sqrt(7u+6)=sqrt(5u+16)#

Square both sides.

#(sqrt(7u+6))^2=(sqrt(5u+16))^2#

#7u+6=5u+16#

Subtract #5u# from both sides.

#7u-5u+6=5u-5u+16#

Simplify.

#2u+6=0+16#

#2u+6=16#

Subtract #6# from both sides.

#2u+6-6=16-6#

Simplify.

#2u+0=10#

#2u=10#

Divide both sides by #2#.

#(color(red)cancel(color(black)(2))^1u)/color(red)cancel(color(black)(2))^1=color(red)cancel(color(black)(10))^5/color(red)cancel(color(black)(2))^1#

Simplify.

#u=5#

Answer 2 · 2018-03-10T02:26:57

#u=5#

#rarrsqrt(7u+6)=sqrt(5u+16)#

#rarr(sqrt(7u+6))^2=(sqrt(5u+16))^2#

#rarr7u+6=5u+16#

#rarr2u=10#

#rarru=5#