Question

How do you find the vertex of `y=x^2+2x-3`?

Answer 1

vertex form of parabola is given as, `y=a(x-h)^2 +k` where, `(h,k)` is the coordinate of vertex

Now givn equation is `y=x^2 +2x-3=x^2+2x+1-4=(x+1)^2-4=(x-(-1))^2+(-4)`

So,coordinate of vertex is `(-1,-4)`

graph{y=x^2+2x-3 [-10, 10, -5, 5]}

See in the graph now.