Question

How do you graph `y=csc(2*theta+π)-3`?

Answer 1

As below.

Explanation:

Standard form of equation for csc is `y = a csc (b theta - c) + d`

`y = csc (2theta + pi) - 3`

Period = (2pi) / |b| = (2pi) / 2 = pi#

Phase shift = c / b = -pi / 2 = -pi/2``color(white)(aaa)pi/2# to the left.

Vertical shift `= d = - 3`

graph{csc (2x + pi) - 3 [-10, 10, -5, 5]}