What is the vertex form of #y= 5x^2-9x-2 #?

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Answer 1 · 2018-03-16T14:18:08

#5(x-9/10)^2-121/20#

We have to write the above in the form #a(x-h)^2+k#

We have:

#5x^2-9x-2#

#5(x^2-9/5x)-2#

#5(x^2-9/5x+81/100)-2-81/20#

#5(x-9/10)^2-121/20#

This is in the above form.

By the way, the vertex is at #(9/10,-121/20)#