How do you graph #y=4csc(x+pi/2)#?

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Answer 1 · 2018-03-18T11:10:00

As detailed below.

Standard form #y = A sin(Bx +C) + D#

Given equation is #y = 4 csc (x + (pi/2))#

#"Amplitude " = "None"# Function csc x doesn't have amplitude.

#"Period " = P = (2pi) / |B| =(2 pi) / 1 = 2pi#

#"Phase Shift " = -c / b = -pi/2# #pi/2 " (to the left)"

# "Vertical Shift" = 0#

graph{4 csc(x + (pi/2)) [-10, 10, -5, 5]}