How do you factor by grouping: #2x^3 + 8x^2 - 7x – 28#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer elsie ☆ Mar 25, 2018 #(x+4)(2x^2-7)# Explanation: #2x^3+8^2-7x-28=0# #2x^2(x+4)-7(x+4)=0# #(x+4)(2x^2-7)=0# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 2069 views around the world You can reuse this answer Creative Commons License